2[3-2(2+4)]=3(4-z)

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Solution for 2[3-2(2+4)]=3(4-z) equation:


Simplifying
2[3 + -2(2 + 4)] = 3(4 + -1z)

Combine like terms: 2 + 4 = 6
2[3 + -2(6)] = 3(4 + -1z)

Multiply -2 * 6
2[3 + -12] = 3(4 + -1z)

Combine like terms: 3 + -12 = -9
2[-9] = 3(4 + -1z)

Multiply 2 * -9
-18 = 3(4 + -1z)
-18 = (4 * 3 + -1z * 3)
-18 = (12 + -3z)

Solving
-18 = 12 + -3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '3z' to each side of the equation.
-18 + 3z = 12 + -3z + 3z

Combine like terms: -3z + 3z = 0
-18 + 3z = 12 + 0
-18 + 3z = 12

Add '18' to each side of the equation.
-18 + 18 + 3z = 12 + 18

Combine like terms: -18 + 18 = 0
0 + 3z = 12 + 18
3z = 12 + 18

Combine like terms: 12 + 18 = 30
3z = 30

Divide each side by '3'.
z = 10

Simplifying
z = 10

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